document.write( "Question 1139283: Solve:\r
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document.write( "1) 5^2X^2^+^3X=25\r
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document.write( "2) 3^-X=7^X+^2\r
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document.write( "3) 250000=100000(1+.06/12)^12(t) \n" );
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Algebra.Com's Answer #757073 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "1) 5^2X^2^+^3X=25 \n" ); document.write( "The sequence of characters \"X^2+^\" has no meaning. \n" ); document.write( "The sequence of characters \"+^3\" has no meaning. \n" ); document.write( "2) 3^-X=7^X+^2 \n" ); document.write( "The sequence of characters \"+^2\" has no meaning. \n" ); document.write( "3) 250000=100000(1+.06/12)^12(t) \n" ); document.write( "The equation as you show it is solved by ordinary arithmetic.... \n" ); document.write( " \n" ); document.write( "The value of t is 250000, divided by the product of 100000 and (1+.06/12)^12. \n" ); document.write( "Surely you meant \n" ); document.write( "3) 250000=100000(1+.06/12)^(12t) \n" ); document.write( "This is now an equation for finding the number of years t that it takes 100000 to increase to 250000 at 6% compounded monthly. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The variable is in the exponent; you need to take logs of both sides. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use a calculator.... \n" ); document.write( " |