document.write( "Question 1139182: If 3.5% of 80,000 parts are defective (2800) then what is the probability of pulling 20,000 random parts with zero defects?
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Algebra.Com's Answer #756984 by ikleyn(53751)\"\" \"About 
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document.write( "From the first statement, the probability for any one part to be defective is  P = 0.035   (which is 3.5%).\r\n" );
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document.write( "It means that the probability for any one part to be fair (with no defects) is  Q = 1 - 0.035 = 0.965.\r\n" );
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document.write( "Then the probability for 20,000 parts to be with zero defects is  \"Q%5E20000\" = \"0.965%5E20000\" = \"%281-P%29%5E20000\".\r\n" );
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document.write( "It is the formula you are asking for.    ANSWER\r\n" );
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