document.write( "Question 1139192: Add A734 (base 12) and 128B (base 12). \n" ); document.write( "

Algebra.Com's Answer #756983 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Addition in base 12 (A=10; B=11)

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document.write( "\r\n" );
document.write( "      A734\r\n" );
document.write( "    + 128B\r\n" );
document.write( "      ----\r\n" );
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document.write( "In base 10, the addition in the rightmost column is 4+11 = 15; in base 12 that is \"13\".  The 3 is the first digit in the sum; the 1 gets \"carried\":\r\n" );
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document.write( "        1\r\n" );
document.write( "      A734\r\n" );
document.write( "    + 128B\r\n" );
document.write( "      ----\r\n" );
document.write( "         3\r\n" );
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document.write( "In base 10, the addition in the next column is 1+3+8 = 12; in base 12 that is \"10\".  The 0 is the next digit in the sum; the 1 gets carried:\r\n" );
document.write( "\r\n" );
document.write( "       11\r\n" );
document.write( "      A734\r\n" );
document.write( "    + 128B\r\n" );
document.write( "      ----\r\n" );
document.write( "        03\r\n" );
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document.write( "In base 10, the addition in the next column is 1+7+2 = 10; in base 12 that is A.  The next digit in the sum is A and there is no carry:\r\n" );
document.write( "\r\n" );
document.write( "       11\r\n" );
document.write( "      A734\r\n" );
document.write( "    + 128B\r\n" );
document.write( "      ----\r\n" );
document.write( "       A03\r\n" );
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document.write( "In the last column, the addition in base 10 is 10+1 = 11; in base 12 that is B.  The last digit in the sum is B and we are done.\r\n" );
document.write( "\r\n" );
document.write( "       11\r\n" );
document.write( "      A734\r\n" );
document.write( "    + 128B\r\n" );
document.write( "      ----\r\n" );
document.write( "      BA03\r\n" );
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