document.write( "Question 1139171: The surface area of a closed cone of height h and base radius r is given by
\n" ); document.write( "A = πr² + πr√(h² + r²).
\n" ); document.write( "Show that h = (A/πr)√(1 - (2πr²/A))
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Algebra.Com's Answer #756951 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"A+=+pi%2Ar%5E2%2B+pi%2Arsqrt%28h%5E2+%2B+r%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+-+pi%2Ar%5E2=pi%2Arsqrt%28h%5E2+%2B+r%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F%28pi%2Ar%29+-+%28pi%2Ar%5E2%29%2F%28pi%2Ar%29+=sqrt%28h%5E2+%2B+r%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A%2F%28pi%2Ar%29+-+r+=sqrt%28h%5E2+%2B+r%5E2%29\"...........square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28A%2F%28pi%2Ar%29+-+r%29%5E2+=h%5E2+%2B+r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28A%2F%28pi%2Ar%29%29%5E2+-2%28Ar%2F%28pi%2Ar%29%29%2Br%5E2-r%5E2+=h%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5E2%2F%28pi%5E2%2Ar%5E2%29+-2A%2Fpi++=h%5E2+\".......common denominator is \"%28pi%5E2%2Ar%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5E2%2F%28pi%5E2%2Ar%5E2%29+-%282A%2Api%2Ar%5E2%29%2F%28pi%5E2%2Ar%5E2%29+=h%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5E2%2F%28pi%5E2%2Ar%5E2%29+-%282A%5E2%2Api%2Ar%5E2%29%2F%28Api%5E2%2Ar%5E2%29+=h%5E2+\" factor out common \"A%5E2%2F%28pi%5E2%2Ar%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28A%5E2%2F%28pi%5E2%2Ar%5E2%29%29%281+-%282pi%2Ar%5E2%29%2FA+%29=h%5E2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=sqrt%28%28A%5E2%2F%28pi%5E2%2Ar%5E2%29%29%29%2Asqrt%28%281+-%282pi%2Ar%5E2%29%2FA+%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=%28A%2F%28pi%2Ar%29%29%2Asqrt%28%281+-%282pi%2Ar%5E2%29%2FA+%29%29\"\r
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