document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1139171>Question 1139171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The surface area of a closed cone of height h and base radius r is given by<BR>\n" );
document.write( "A = πr² + πr√(h² + r²). <BR>\n" );
document.write( "Show that h = (A/πr)√(1 - (2πr²/A)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756950 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The question is asking to solve for h.  Mostly simple algebra.\r<BR>\n" );
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document.write( "One of your steps should lead to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=sqrt%28%28%28A-pi%2Ar%5E2%29%2F%28pi%2Ar%29%29%5E2-r%5E2%29 ALIGN=MIDDLE  ALT=\"h=sqrt%28%28%28A-pi%2Ar%5E2%29%2F%28pi%2Ar%29%29%5E2-r%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
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document.write( ".<BR>\n" );
document.write( " </SPAN>\n" );
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