document.write( "Question 1139149: Luke hiked up a 41/2-mile trail to the top of Mt. Washington at an average speed of 21/7 mph. His dad hiked the same trail at an average speed of 21/4 mph. If Luke’s dad reaches the top of the mountain at noon, at what time will Luke arrive? \n" ); document.write( "
Algebra.Com's Answer #756944 by josgarithmetic(39617)\"\" \"About 
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document.write( "              SPEED            TIME           DISTANCE\r\n" );
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document.write( "Luke          \"21%2F7=3\"                           \"4%261%2F2\"\r\n" );
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document.write( "Dad           \"21%2F4=5%261%2F4\"                         \"4%261%2F2\"\r\n" );
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\n" ); document.write( "\n" ); document.write( "Time quantities easily filled in, \"T=D%2FR\".\r
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document.write( "              SPEED            TIME           DISTANCE\r\n" );
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document.write( "Luke          \"21%2F7=3\"         \"1%261%2F2\"                \"4%261%2F2\"\r\n" );
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document.write( "Dad           \"21%2F4=5%261%2F4\"       \"6%2F7\"               \"4%261%2F2\"\r\n" );
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\n" ); document.write( "\n" ); document.write( "The extra time Luke needed compared to his dad, \"1%261%2F2-6%2F7=9%2F14\"\"hours\". If dad reached top at noon, then Luke reached top \"9%2F14\" hours later, or 0.64286 hour, or 39 minutes. \n" ); document.write( "
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