document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1139150>Question 1139150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if log 2 = 0,301 and log 3 = 0,477 solve the following:\r<BR>\n" );
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document.write( "2log6 + log12 - log6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756925 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2log6=2*(log3+log2)=2(0.778)=1.556<BR>\n" );
document.write( "log 12=2 log 2+log 3, which is log 4+log 3=1.079<BR>\n" );
document.write( "log 6 is 0.778<BR>\n" );
document.write( "The result is 1.857<BR>\n" );
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