document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1139029>Question 1139029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a pile of 37 coins consists of nickels and dimes. the total value of the coins is 3.10. find the number of each type of coin </SPAN>\n" );
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document.write( "(1) Algebra with two variables<br><BR>\n" );
document.write( "n+d = 37  (the total number of nickels (n) and dimes (d) is 37)<BR>\n" );
document.write( "5n+10d = 310  (the total value of the coins is 310 cents)<br><BR>\n" );
document.write( "Solve by whatever method you choose.<br><BR>\n" );
document.write( "(2) Algebra with one variable<br><BR>\n" );
document.write( "5n+10(37-n) = 310  (if the number of nickels is n and the total number of coins is 37, then the number of dimes is 37-n)<br><BR>\n" );
document.write( "Solve using basic algebra.<br><BR>\n" );
document.write( "(3) Using logical reasoning and mental arithmetic<br><BR>\n" );
document.write( "> if all 37 coins were nickels, the total value would be 37*5 = 185 cents<BR>\n" );
document.write( "> the actual total value is 310 cents, which is 125 cents more than 185 cents<BR>\n" );
document.write( "> exchanging a nickel for a dime keeps the total number of coins the same and increases the total value by 5 cents<BR>\n" );
document.write( "> the number of nickels to be exchanged for dimes to make the additional 125 cents is 125/5 = 25<br><BR>\n" );
document.write( "So there are 25 dimes and 37-25 = 12 nickels </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );