document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138969>Question 1138969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kevin and randy Muise have a jar containing 53 coins, all of which are eathir quarters or nickels. The total value of the coins in the jar is $6.05. How many of each type of coin do they have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756787 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If you don't need a formal algebraic solution to a problem like this, here is a quick way to get the answer with logical reasoning and some mental arithmetic.<br><BR>\n" );
document.write( "(1) If all 53 coins were nickels; the total value would be 53*$0.05 = $2.65.  That's $3.40 short of the actual total of $6.05.<br><BR>\n" );
document.write( "(2) The difference between the value of each quarter and each nickel is 20 cents.<br><BR>\n" );
document.write( "(3) So to make up those additional $3.40 (340 cents), the number of quarters must be 340/20 = 17.<br><BR>\n" );
document.write( "ANSWER: 17 quarters and (53-17) = 36 nickels </SPAN>\n" );
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