document.write( "Question 1138898: sketch a graph of a function f(x) on the interval -2 (less than or equal to) x (less than or equal to) 2 with the following properties. Label any points on the x-axis or y-axis which are important.
\n" ); document.write( "f is odd.
\n" ); document.write( "f\"(x) is positive for all x>0.
\n" ); document.write( "f'(0) is negative.
\n" ); document.write( "f'(1) = 0.
\n" ); document.write( "f(2) = 0.\r
\n" ); document.write( "\n" ); document.write( "thanks for helping!!
\n" ); document.write( "

Algebra.Com's Answer #756784 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "(1) f(x) is odd.

\n" ); document.write( "That means the graph is symmetric with respect to the origin.
\n" ); document.write( "That in turn means that f(0) = 0.

\n" ); document.write( "(2) f''(x) is positive for all x > 0.

\n" ); document.write( "That means the graph is concave up for all x > 0.
\n" ); document.write( "The fact that f(x) is odd then means the graph is concave down for all x < 0.

\n" ); document.write( "(3) f'(0) is negative.

\n" ); document.write( "That means the slope of the graph at x=0 is negative (downhill to the right).

\n" ); document.write( "(4) f'(1) = 0.

\n" ); document.write( "That means the slope of the graph is 0 (the tangent to the graph is horizontal) at x=1.
\n" ); document.write( "That in turn means the slope is also 0 at x = -1.

\n" ); document.write( "(5) f(2) = 0.

\n" ); document.write( "That means that f(-2) = 0 also.

\n" ); document.write( "I can't draw a graph of such a function, because no kind of graph that I know how to graph with the tools on this forum has all those characteristics.

\n" ); document.write( "The graph below of the polynomial \"y+=+x%5E3-4x+=%28x%2B2%29%28x%29%28x-2%29\" almost works, except that the slopes of 0 are not at exactly x=1 and x=-1.

\n" ); document.write( "\"graph%28400%2C400%2C-3%2C3%2C-10%2C10%2Cx%5E3-4x%29\"
\n" ); document.write( "
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