document.write( "Question 1138948: The monthly revenue R achieved by selling x wristwatches is figured to be
\n" ); document.write( "R(x)=75x−0.2x^2.  The monthly cost C of selling x wristwatches is C(x)=28x+1650.
\n" ); document.write( "​(a) How many wristwatches must the firm sell to maximize​ revenue? What is the maximum​ revenue?
\n" ); document.write( "​(b) Profit is given as P(x)=R(x)−C(x). What is the profit​ function?
\n" ); document.write( "​(c) How many wristwatches must the firm sell to maximize​ profit? What is the maximum​ profit?
\n" ); document.write( "​(d) Provide a reasonable explanation as to why the answers found in parts​ (a) and​ (c) differ. Explain why a quadratic function is a reasonable model for revenue.
\n" ); document.write( "

Algebra.Com's Answer #756753 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Revenue=75x-0.2x^2
\n" ); document.write( "this is a quadratic with maximum at vertex where x=-b/2a=-75/-0.4=187.5
\n" ); document.write( "maximum revenue is $7031.20 for both 187 and 188 watches.
\n" ); document.write( "profit is the difference between these two, or -0.2x^2+47x-1650
\n" ); document.write( "This is maximized for x=-47/-0.4 or 117.5 watches
\n" ); document.write( "f(117.5)=$1111.25\r
\n" ); document.write( "\n" ); document.write( "they differ because there are two different quadratics, basically. The third graph has a difference between the two. Cost increases linearly, revenue will increase up to a point where beyond which more being sold and then decrease, either because of decrease in demand, oversupply, or other factors.
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C150%2C-100%2C2000%2C-.2x%5E2%2B47x-1650%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C220%2C-500%2C10000%2C75x-0.2x%5E2%29\"
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C220%2C-2000%2C10000%2C75x-0.2x%5E2%2C28x%2B1650%29\"
\n" ); document.write( "
\n" );