document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138949>Question 1138949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diana has available 400 yards of fencing and wishes to enclose a rectangular area.<BR>\n" );
document.write( "​(a) Express the area A of the rectangle as a function of the width W of the rectangle.<BR>\n" );
document.write( "​(b) For what value of W is the area​ largest?<BR>\n" );
document.write( "​(c) What is the maximum​ area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756741 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw this<BR>\n" );
document.write( "sides are x x and 400-2x<BR>\n" );
document.write( "The area is x(400-2x)=-2x^2+400x<BR>\n" );
document.write( "the vertex for this quadratic is a maximum and will have x value of -b/2a=-400/-4=100 yds<BR>\n" );
document.write( "the maximum area for this 100*200 rectangle is 20000 yds^2.\r<BR>\n" );
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document.write( "The formula for A=-2W2+400W for W=width </SPAN>\n" );
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