document.write( "Question 1138879: Express 2 - 2i in polar form using principal argument \n" ); document.write( "
Algebra.Com's Answer #756728 by MathLover1(20849)\"\" \"About 
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Express \"2+-+2i\" in polar form using principal argument \r
\n" ); document.write( "\n" ); document.write( "\"z=2+-+2i\"=>\"z=x+-+yi\"\r
\n" ); document.write( "\n" ); document.write( "The modulus (or length) of the complex number is simply given by using Pythagoras' theorem to find the hypotenuse, ie\r
\n" ); document.write( "\n" ); document.write( "\"z=r%2Acos%28theta%29%2Br%2Ai%2Asin%28theta%29\"
\n" ); document.write( "\"z=r%28cos%28theta%29%2Bi%2Asin%28theta%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"z=2+-+2i\"
\n" ); document.write( "\"r%2Acos%28theta%29=2\"
\n" ); document.write( "\"r%2Asin%28theta%29=-2\"
\n" ); document.write( "=>\"tan%28theta%29=-2%2F2=-1\"\r
\n" ); document.write( "\n" ); document.write( "will be easier to find acute angle in quadrant I whose tan is \"1\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha=tan%5E%28-1%29%281%29=pi%2F4\" or \"alpha=45\"°\r
\n" ); document.write( "\n" ); document.write( "now find \"r\"
\n" ); document.write( "\"r=sqrt%282%5E2%2B%28-2%29%5E2%29\"
\n" ); document.write( "\"r=sqrt%288%29\"
\n" ); document.write( "\"r=sqrt%284%2A2%29\"
\n" ); document.write( "\"r=2sqrt%282%29\"\r
\n" ); document.write( "\n" ); document.write( "=> \"r\" is in quadrant IV
\n" ); document.write( "=> \"theta=360-alpha=360-45=315\"° or
\n" ); document.write( "\"theta=2pi-alpha=2pi-pi%2F4=7pi%2F4\"=> we can also choose to use \"theta=-alpha\" which is also in quadrant IV\r
\n" ); document.write( "\n" ); document.write( "so, \"theta=45\"° or \"theta=-pi%2F4\"\r
\n" ); document.write( "\n" ); document.write( "then we have\r
\n" ); document.write( "\n" ); document.write( "\"z=2sqrt%282%29%28cos%28-pi%2F4%29%2Bi%2Asin%28-pi%2F4%29%29\"......since \"cos%28-pi%2F4%29=cos%28pi%2F4%29\" and \"sin%28-pi%2F4%29=+-sin%28pi%2F4%29\", we have\r
\n" ); document.write( "\n" ); document.write( "\"z=2sqrt%282%29%28cos%28pi%2F4%29-i%2Asin%28pi%2F4%29%29\"
\n" ); document.write( "or using\"theta=45\"° , we have \"z=2sqrt%282%29%28cos%2845%29-i%2Asin%2845%29%29\"\r
\n" ); document.write( "\n" ); document.write( "also, using \"theta=7pi%2F4\" or \"theta=315\"° :\r
\n" ); document.write( "\n" ); document.write( "\"z=2sqrt%282%29%28cos%287pi%2F4%29%2Bi%2Asin%287pi%2F4%29%29\"
\n" ); document.write( "or \"z=2sqrt%282%29%28cos%28315%29%2Bi%2Asin%28315%29%29\"\r
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