document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138896>Question 1138896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> algebraic word pain in the ass problems:<BR>\n" );
document.write( "Cookies are set out on a tray for 6 people to take home. one-third, one-fourth, one-eighth, and one-fifth are given to 4 people. The fifth person eats 10 cookies on the spot, with 1 remaining for the 6th person. Find the original number of cookies on the tray.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756672 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If x is the number of cookies, then the number of cookies the first four people get are (1/3)x, (1/4)x, (1/8)x, and (1/5)x.  The last two people get 10 cookies and 1 cookie.<br><BR>\n" );
document.write( "So the total number of cookies, x, is equal to (1/3)x+(1/4)x+(1/8)x+(1/5)x+10+1.  That gives a simple equation to solve for x:br><BR>\n" );
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document.write( "NB: the LCD for 3, 4, 5, and 8 is 120 </SPAN>\n" );
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