document.write( "Question 1137916: Given 2 < a < 3 and 5 < b < 6 Find:
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Algebra.Com's Answer #756643 by Edwin McCravy(20062) $\"\"$ $\"About$

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document.write( "Given 2 < a < 3 and 5 < b < 6 Find:\r\n" );
document.write( "a. __ < a-b < __\r\n" );
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document.write( " 5 <  b <  6 \r\n" );
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document.write( "multiplying through by -1 flips inequalities:\r\n" );
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document.write( "-5 > -b > -6 \r\n" );
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document.write( "That is equivalent to\r\n" );
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document.write( "-6 < -b < -5\r\n" );
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document.write( "We add that term by term to 2 < a < 3\r\n" );
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document.write( " 2 < a   <  3 \r\n" );
document.write( "-6 <  -b < -5\r\n" );
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document.write( "-4 < a-b < -2\r\n" );
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document.write( "b. __ < a/b < __\r\n" );
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document.write( "is an interval of all positive numbers,\r\n" );
document.write( "The interval of reciprocals are in the opposite \r\n" );
document.write( "order of inequality:\r\n" );
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document.write( "and that is equivalent to\r\n" );
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document.write( "So we multiply 2 < a < 3 term by term by that:\r\n" );
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document.write( "Edwin

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