document.write( "Question 1138862: A school did a survey for a month, they found out that 56% of students buy milk and 32% buy fruit everyday. If 22% of student buy both milk and fruit, what is the percentage of students that buy neither. \n" ); document.write( "

Algebra.Com's Answer #756642 by ikleyn(52794) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " This problem is to be solved in two steps.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Find the percentage of those who buys some of these two products.\r
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document.write( "    It is  56% + 32% - 22% = 66%.\r\n" );
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document.write( "    In this formula, it should be clear to you why I added  56% and 32%.\r\n" );
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document.write( "    why I subtracted 22% ?  - Because when I added, I counted TWICE those who buys both products.\r\n" );
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document.write( "    Step 1 is completed.\r\n" );
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\n" ); document.write( "\n" ); document.write( "STEP 2. Find the percentage of students that buy neither.\r
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document.write( "    It is simply complement of 66% to 100%, and it is equal to\r\n" );
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document.write( "        100% - 66% = 34%.\r\n" );
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document.write( "    It is your final answer.\r\n" );
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