document.write( "Question 1138804: Joe is 35 and his son is 5. In how many years will Joe be exactly three times as old as his son? \n" ); document.write( "
Algebra.Com's Answer #756582 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Joe is \"35\" and his son is \"5\". \r
\n" ); document.write( "\n" ); document.write( "In \"x\" years will Joe be exactly three times as old as his son:\r
\n" ); document.write( "\n" ); document.write( "\"35%2Bx=3%285%2Bx%29\"\r
\n" ); document.write( "\n" ); document.write( "\"35%2Bx=15%2B3x\"\r
\n" ); document.write( "\n" ); document.write( "\"35-15=3x-x\"\r
\n" ); document.write( "\n" ); document.write( "\"20=2x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10\"\r
\n" ); document.write( "\n" ); document.write( "answer: In \"10\" years will Joe be exactly three times as old as his son.\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "now, Joe is \"35\" and his son is \"5\"\r
\n" ); document.write( "\n" ); document.write( "in \"10\" years, Joe is \"45\" and his son is \"15\"\r
\n" ); document.write( "\n" ); document.write( "and \"45=3%2A15\" which confirms our solution\r
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