document.write( "Question 1138794: algebraic word problems:\r
\n" ); document.write( "\n" ); document.write( "The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find the length and the width.\r
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Algebra.Com's Answer #756581 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = the length in cm
\n" ); document.write( "\"+%283%2F4%29%2Ax+\" = the width in cm
\n" ); document.write( "Use formula for perimeter
\n" ); document.write( "\"+2%2A%28+x+%2B+2+%29+%2B+2%2A%28+%283%2F4%29%2Ax+%2B+2+%29+=+50+\"
\n" ); document.write( "\"+2x+%2B+4+%2B+%283%2F2%29%2Ax+%2B+4+=+50+\"
\n" ); document.write( "\"+%28+7%2F2+%29%2Ax+=+42+\"
\n" ); document.write( "\"+7x+=+84+\"
\n" ); document.write( "\"+x+=+12+\"
\n" ); document.write( "and
\n" ); document.write( "\"+%283%2F4%29%2A12+=+9+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "Length = 12 cm
\n" ); document.write( "Width = 9 cm
\n" ); document.write( "-----------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+2%2A%28+12+%2B+2+%29+%2B+2%2A%28+9+%2B+2+%29+=+50+\"
\n" ); document.write( "\"+28+%2B+22+=+50+\"
\n" ); document.write( "\"+50+=+50+\"
\n" ); document.write( "OK
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