document.write( "Question 1138773: A local concert sells out for their show. They sell all 500 tickets for a total purse of $8,070.00. The tickets were priced at $15 for students (s), $12 for children (c), and $18 for adults (a). If the band sold three times as many adult tickets as children’s tickets, how many of each type was sold?\r
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Algebra.Com's Answer #756560 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "This problem can be a good example for comparing the method of solving the problem with three variables (as suggested by the statement of the problem) to the method of solving it with a single variable.

\n" ); document.write( "While it is important to know how to solve a problem involving a system of equations in several variables, very often the amount of effort required to solve the problem is far less with a single equation in one variable.

\n" ); document.write( "A solution using 3 variables....

\n" ); document.write( "c = number of children's tickets
\n" ); document.write( "s = number of student tickets
\n" ); document.write( "a = number of adult tickets

\n" ); document.write( "(1) \"a%2Bs%2Bc+=+500\" the total number of tickets was 500
\n" ); document.write( "(2) \"a+=+3c\" the number of adult tickets was 3 times the number of children's tickets
\n" ); document.write( "(3) \"12c%2B15s%2B18a+=+8070\" the total cost of the tickets was $8070

\n" ); document.write( "Substitute (2) in (1) and (3) to eliminate a, giving two equations in s and c:

\n" ); document.write( "(4) \"3c%2Bs%2Bc+=+500\" --> \"s%2B4c+=+500\"
\n" ); document.write( "(5) \"12c%2B15s%2B18%283c%29+=+8070\" --> \"15s%2B66c+=+8070\"

\n" ); document.write( "Eliminate s between (4) and (5) by multiplying (4) by -15 and adding:

\n" ); document.write( "\"-15s-60c+=+-7500\"
\n" ); document.write( "\"15s%2B66c+=+8070\"
\n" ); document.write( "\"6c+=+570\"
\n" ); document.write( "\"c+=+95\"

\n" ); document.write( "The number of children's tickets was c = 95.

\n" ); document.write( "Then the number of adult tickets was 3c = 285.

\n" ); document.write( "The total number of adult and children's tickets was 95+285 = 380; so the number of student tickets was 500-380 = 120.

\n" ); document.write( "ANSWER: 95 children's tickets, 120 student tickets, 285 adult tickets.

\n" ); document.write( "A solution using one variable....

\n" ); document.write( "let x = number of children's tickets
\n" ); document.write( "then 3x = number of adult tickets (3 times as many as children's)
\n" ); document.write( "and (500-4x) = number of student tickets (the total of 500, minus the adult and children's tickets)

\n" ); document.write( "The total cost was $8070:

\n" ); document.write( "\"12x%2B15%28500-4x%29%2B18%283x%29+=+8070\"
\n" ); document.write( "\"12x%2B7500-60x%2B54x+=+8070\"
\n" ); document.write( "\"6x+=+570\"
\n" ); document.write( "\"x+=+95\"

\n" ); document.write( "ANSWER:
\n" ); document.write( "children: x = 95
\n" ); document.write( "students: 500-4x = 500-380 = 120
\n" ); document.write( "adults: 3x = 285
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