document.write( "Question 1138774: A sorority held a bake sale to raise money and sold brownies and chocolate chip cookies. They priced the brownies at $2 and the chocolate chip cookies at $1, raising $250 and selling 175 items. How many brownies (b) and how many cookies (c) were sold?\r
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Algebra.Com's Answer #756555 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "b = # of brownies
\n" ); document.write( "c = # of chocolate chip cookies

\n" ); document.write( "(1) \"b%2Bc+=+175\" the total number of items sold was 175
\n" ); document.write( "(2) \"2b%2Bc+=+250\" the total cost of the items, at $2 each for the brownies and $1 each for the cookies, was $250

\n" ); document.write( "Solve the equations by whatever method you choose. Elimination certainly looks the easiest, since subtracting the first equation from the second immediately give you the value of b:

\n" ); document.write( "\"b+=+75\"

\n" ); document.write( "So 75 brownies and 100 chocolate chip cookies were sold.

\n" ); document.write( "You can get the answer using virtually the same calculations informally, using logical reasoning instead of formal algebra:

\n" ); document.write( "(1) If all 175 items were cookies, the total sales would be $175; but the actual total is $250, which is $75 more than that.
\n" ); document.write( "(2) Each brownie costs $1 more than each cookie.
\n" ); document.write( "(3) Therefore, to make the additional $75, the number of brownies that was sold has to be $75/$1 = 75.
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