document.write( "Question 1138716: The Ram Company borrowed $20 000 at 10% compounded semi-annually and made payments toward the loan of $8000 after two years and $10 000 after three-and-a-half years. How much is required to pay off the loan one year after the second payment?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #756535 by Theo(13342) You can put this solution on YOUR website! they borrowed 20,000 at 10% compounded semi-annually.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the interest rate per half year time period was 10% / 2 = 5% / 100 = .05.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the number of half year periods was equal to 2 times the number of years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they made payment of $8,000 at the end of 2 years and $10,000 at the end of 3.5 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the remaining balance on the loan started at 10,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of 2 years after the loan was made, the remaining balance of the loan after interest was added but before payment was made was equal to $10,000 * 1.05 ^ 4 = $24,310.13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they made their payment of $8,000 and the remaining balance on the loan after interest added and payment was subtracted was equal to $24,310.13 minus $8,000 = $16,310.13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of 3.5 years, which was 1.5 years after the end of 2 years, the remaining balance on the loan was $16,310.13 * 1.05 ^ 3 = $18,881.01 after interest was added but before payment was made.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they made their payment of $10,000 and the remaining balance on the loan after interest was added and payment was made became equal to $8,881.01.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "one year after that, the remaining balance on the loan was 8,881.01 * 1.05 ^ 2 = 9,791.31.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's how much was required to pay off the loan one year after the last payment was made.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this can be seen in more detail in the following excel spreadsheet printout.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula used is f = p * (1 + r) ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the time period is in half years. \n" ); document.write( "the rate per half year is 10% / 100 = .10 / 2 = .05 per half year. \n" ); document.write( "the number of half years is 2 times the number of years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 + r becomes (1 + .05) which becomes 1.05.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |