\r\n" );
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document.write( "We want to multiply through by the LCD of x+5.\r\n" );
document.write( "But if x+5 is negative, the inequality symbol will reverse.\r\n" );
document.write( "So we must take two cases:\r\n" );
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document.write( "Case 1: x+5>0 or x>-5\r\n" );
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document.write( "
\r\n" );
document.write( "We are multiplying through by a positive number, so we keep\r\n" );
document.write( "the same inequality symbol\r\n" );
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document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
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document.write( "This contradicts x>-5, so Case 1 must be discarded.\r\n" );
document.write( "\r\n" );
document.write( "Case 2: x+5<0 or x<-5\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "We are multiplying through by a negative number, so we reverse\r\n" );
document.write( "the inequality symbol\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
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document.write( "However, case 2 requires that x<-5\r\n" );
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document.write( "So the graph of the solution is\r\n" );
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document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "which can be written as\r\n" );
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document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "or in interval notation as\r\n" );
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document.write( "[-8,-5)\r\n" );
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document.write( "A bracket on the left to show that -8 is included\r\n" );
document.write( "and a parenthesis on the right.\r\n" );
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document.write( "Edwin
\r
\n" );
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document.write( " \n" );
document.write( "