document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138576>Question 1138576</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a boat charter is $1800.00 with room for 100 people and the tickets are 30.00 each and there is a variable food and drink expense of 15.00 per person. How many tickets must be sold to break even? \r<BR>\n" );
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document.write( "I got: 1800 + 1500 = 3300 so 100 people x $30.00 only get you $3000.00 <BR>\n" );
document.write( "They need to sell 110 tickets to break even and there is only 100 spots? Is 110 tickets right?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756363 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C=1800+15x is the fixed and variable cost, where x is the number of people<BR>\n" );
document.write( "30x is the revenue<BR>\n" );
document.write( "30x=1800+15x is breakeven equation<BR>\n" );
document.write( "15x=1800<BR>\n" );
document.write( "x=120.  One won't break even with fewer than 120 people<BR>\n" );
document.write( "Remember, as one sells a ticket, the gain is only $15, since another $15 is food/drink.\r<BR>\n" );
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document.write( "It is true that with 110 tickets, one will have $3300, but the costs are $1800 + (110*$15), because there are 110 people with food and drink expenses, so that is added to the cost and it is $1650 for a total cost of $3450.  The revenue is 110*$30 or $3300. </SPAN>\n" );
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