document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138532>Question 1138532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An ice cream parlor has one size of ice-cream cone for 7 cents and another for a cents. One afternoon when the smaller cones outsold the larger ones two to one, the sale totaled 6.21 pesos. How many cones of each size were sold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756345 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = the number of cones selling for 7 cents each.<BR>\n" );
document.write( "y = the number of cones selling for a cents each. \r<BR>\n" );
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document.write( "one afternoon the smaller cones outsold the larger cones two to one for a total sale of 6.21 pesos.\r<BR>\n" );
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document.write( ".07 * x + a * y = 6.21\r<BR>\n" );
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document.write( "since y = 2x, the formula becomes:\r<BR>\n" );
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document.write( ".07 * x + a * 2x = 6.21.\r<BR>\n" );
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document.write( "factor out the x to get x * (.07 + 2a) = 6.21.\r<BR>\n" );
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document.write( "solve for x to get x = 6.21 / (.07 + 2a).\r<BR>\n" );
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document.write( "your answer depends on the value of a.\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "if the value of a = .01, then the formula becomes x = 6.21 / (.07 + 2 * .01) which becomes x= 6.21 / .09.\r<BR>\n" );
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document.write( "this results in x = 69.\r<BR>\n" );
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document.write( "since y = 2x, then y = 138.\r<BR>\n" );
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document.write( ".07 * x + .01 * y becomes .07 * 69 + .01 * 138 which is equal to 6.21.\r<BR>\n" );
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document.write( "if the value of a is anything else, like .05, then x = 6.21 / (x + 2a) becomes x = 6.21 / (x + .10) which becomes x = 6.21 / .17 which then becomes x = 36.52941176.\r<BR>\n" );
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document.write( "this makes y = 73.05882353.\r<BR>\n" );
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document.write( ".07x + .05y becomes .07 * 36.52941176 + .05 * 73.05882353 = 6.21.\r<BR>\n" );
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document.write( "thye formula works for any value of a, but you do need the value of a in order to find the value of x which you then double to find the value of y.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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