document.write( "Question 1138496: third degree, only real coefficients, −2 and 2+i are two of the zeros, y-intercept is −20. \n" ); document.write( "
Algebra.Com's Answer #756298 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the third zero is 2-i, since complex roots are conjugate.\r \n" ); document.write( "\n" ); document.write( "(x+2)(x-2-i)(x-2+i) are factors \n" ); document.write( "multiply the second and third. \n" ); document.write( "x^2-2x+ix. -2x+4-2i. -ix+2i-i^2 \n" ); document.write( "This is x^2-4x+5, remembering that i^2 is -1, so that -i^2=+1 \n" ); document.write( "the polynomial is x^3+2x^2-4x^2-8x+5x+10=x^3-2x^2-3x+10 \n" ); document.write( "a(x^3-2x^2-3x+10) has to give a y-intercept of -20 \n" ); document.write( "so a is -2 \n" ); document.write( "-2x^3+4x^2+6x-20 is the polynomial.\r \n" ); document.write( "\n" ); document.write( " |