document.write( "Question 1138449: Find the product in the base indicated.\r
\n" ); document.write( "\n" ); document.write( "37 (base 8) * 21 (base 8) \n" ); document.write( "

Algebra.Com's Answer #756254 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "(1) 37*1 in base 8 (or in ANY base) is 37.

\n" ); document.write( "(2) 37*2 in base 8 is 76:
\n" ); document.write( "7*2=14 (base 10) = 16 (base 8) so the last digit is 6; carry the 1
\n" ); document.write( "3*2=6, plus the carry of 1 makes 7
\n" ); document.write( "So 37*2 in base 8 is 76.

\n" ); document.write( "Then 37 (base 8) times 21 (base 8) is, in base 8,

\r\n" );
document.write( "  \r\n" );
document.write( "    37\r\n" );
document.write( "  * 21\r\n" );
document.write( "  ----\r\n" );
document.write( "    37\r\n" );
document.write( "   76\r\n" );
document.write( "  ----\r\n" );
document.write( "  1017

\n" ); document.write( "The last digit in the product is 7.
\n" ); document.write( "The next digit is 3+6 which is 9 in base 10 but 11 in base 8; this digit is 1 and carry the other 1.
\n" ); document.write( "Then 7 plus the carry of 1 makes 8, which is 10 in base 8; since there are no more columns to add, write the 10 as the first two digits.

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