document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138425>Question 1138425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE SIDE OF AN EQUILATERAL TRIANGLE ARE GIVEN AS(3x+2)cm, (2y-x)cm and (y+3)cm.find x and y, and the perimeter of the triangle.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756221 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sides are equal<BR>\n" );
document.write( "so 3x+2=2y-x=y+3<BR>\n" );
document.write( "2y-x=y+3<BR>\n" );
document.write( "y-3=x<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "3(y-3)+2=y+3<BR>\n" );
document.write( "3y-9+2=y+3<BR>\n" );
document.write( "2y=10<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "the sides are 8, 8, 8 with perimeter 24. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );