document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138413>Question 1138413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist mixes a 5% salt solution with an 11% salt<BR>\n" );
document.write( "solution. How many milliliters of each should be used to make<BR>\n" );
document.write( "600 milliliters of a 7% salt solution?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756213 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a solution using an alternative to the usual algebraic methods.  If you understand this method, it will get you to the answer to mixture problems like this much faster and with far less work than any of the algebraic methods.<br><BR>\n" );
document.write( "(1) The target percentage (7) is 1/3 of the way from the lower percentage (5) to the higher percentage (11).<br><BR>\n" );
document.write( "(It might help you see what I'm saying there by plotting the 5, 7, and 11 on a number line; 7 is 1/3 of the way from 5 to 11.)<br><BR>\n" );
document.write( "(2) That means 1/3 of the mixture has to be the higher percentage.<br><BR>\n" );
document.write( "ANSWER: 1/3 of 600ml, or 200ml of 11%; so 400ml of 5%.<BR>\n" );
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