document.write( "Question 1138393: Express cos 236° in terms of its reference angle. Show work. \n" ); document.write( "
Algebra.Com's Answer #756196 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "A reference angle is an angle whose measure is between \"0\"° and\"+90\"° (not including \"0\"° or \"90\"°)\r
\n" ); document.write( "\n" ); document.write( "If \"theta\" is your angle, here’s how to find its reference angle.\r
\n" ); document.write( "\n" ); document.write( "Quadrant |Reference Angle
\n" ); document.write( " II............ |< \"180\"° - \"theta\"
\n" ); document.write( " III ...........|< \"theta\" - \"180\"°
\n" ); document.write( " IV............| < \"360\"° - \"theta\"\r
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\n" ); document.write( "\n" ); document.write( "=> \"sin+%28236+%29\" ° \r
\n" ); document.write( "\n" ); document.write( "= > \"+236+\" ° is in Q II where sin is negative, so reference angle is: \"236-180=56+\"\r
\n" ); document.write( "\n" ); document.write( "=>\"sin+%28236+%29+=+-sin+%2856%29\"\r
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