document.write( "Question 1138398: Express sin 485° in terms of its reference angle. Show work. \n" ); document.write( "
Algebra.Com's Answer #756191 by MathLover1(20850)\"\" \"About 
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Express \"sin%28485%29\"° in terms of its reference angle. Show work
\n" ); document.write( "\"485\"° is equal to \"360%2B125\"°; so, you look for \"125\"° which is in Q II\r
\n" ); document.write( "\n" ); document.write( "note:
\n" ); document.write( "A reference angle is an angle whose measure is between \"0\"° and\"+90\"° (not including \"0\"° or \"90\"°)\r
\n" ); document.write( "\n" ); document.write( "If \"theta\" is your angle, here’s how to find its reference angle.\r
\n" ); document.write( "\n" ); document.write( "Quadrant |Reference Angle
\n" ); document.write( " II............ | <\"180\"° - \"theta\"
\n" ); document.write( " III ...........|< \"theta\" - \"180\"°
\n" ); document.write( " IV............| < \"360\"° - \"theta\"\r
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\n" ); document.write( "\n" ); document.write( "then, reference angle is: \r
\n" ); document.write( "\n" ); document.write( "\"sin%28485%29\"° = \"sin%28125%29\"° \r
\n" ); document.write( "\n" ); document.write( " reference angle: \"180-125=55\"°\r
\n" ); document.write( "\n" ); document.write( "=>\"+sin%28485%29+=+sin%2855%29\"\r
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