document.write( "Question 1138315: 99.7% of the scores on an exam are between 60 and 98 points. Assuming the data is normally distributed, what are the mean and standard deviation? \n" ); document.write( "
Algebra.Com's Answer #756145 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 99.7% is +/- 3 sd \n" ); document.write( "The mean is half the sum of 60 and 98 or 79 \n" ); document.write( "The difference between 60 and 79 and 79 and 98 is 19 \n" ); document.write( "each of those is 3 sd \n" ); document.write( "so the sd is 19/3 \n" ); document.write( "N (69, 19/3) \n" ); document.write( " |