document.write( "Question 1138274: The altitude of a regular cone is twice its base radius. if its volume is 3,400 cubic meter what is the total surface area? \n" ); document.write( "
Algebra.Com's Answer #756122 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
The altitude of a regular cone is twice its base radius. if its volume is \"3400\" cubic meter what is the total surface area? \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the base of a cone is a circle, the formula for finding the volume of a cone is:\r
\n" ); document.write( "\n" ); document.write( "\"V=%281%2F3%29pi%2Ar%5E2%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "the altitude of a regular cone is twice its base radius:\"h=2r\"\r
\n" ); document.write( "\n" ); document.write( "\"volume+is+V=3400\"\r
\n" ); document.write( "\n" ); document.write( "\"3400=%281%2F3%29pi%2Ar%5E2%2A2r\"\r
\n" ); document.write( "\n" ); document.write( "\"3400=%282pi%2F3%29r%5E3+\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E3=3400%2F%282%2F3%29pi\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E3=%283%2A3400%29%2F2pi\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E3=5100%2Fpi\"\r
\n" ); document.write( "\n" ); document.write( "\"r=root%283%2C5100%2Fpi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=11.75\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The total surface area of a cone is the sum of the area of its base and the lateral (side) surface.\r
\n" ); document.write( "\n" ); document.write( "the formula for the lateral surface area of a right cone is
\n" ); document.write( "\"L_S_A=+pi%2Ar%2Al\" , where l is the slant height of the cone \r
\n" ); document.write( "\n" ); document.write( "use \"r\" and \"h\" to find the slant height \"l\"
\n" ); document.write( "\"l=sqrt%28r%5E2%2Bh%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"l=sqrt%2811.75%5E2%2B%282%2A11.75%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"l=26.27\"\r
\n" ); document.write( "\n" ); document.write( "\"L_S_A=+pi%2A11.75%2A26.27\"\r
\n" ); document.write( "\n" ); document.write( "\"L_S_A=+969.72cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "area of the base: \r
\n" ); document.write( "\n" ); document.write( "\"B_A=r%5E2pi\"\r
\n" ); document.write( "\n" ); document.write( "\"B_A=11.75%5E2%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"B_A=433.74cm%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=>The total surface area of a cone is:\r
\n" ); document.write( "\n" ); document.write( "\"A=B_A%2BL_S_A\"\r
\n" ); document.write( "\n" ); document.write( "\"A=433.74cm%5E2%2B969.72cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"A=1403.46cm%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );