document.write( "Question 1138285: There are 21 coins in a jar consisting of quarters nickels and dimes. If there are twice as many dimes as nickels and there is a total of $2.75 in the jar, how many of each coin are there? \n" ); document.write( "

Algebra.Com's Answer #756111 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "Let N be the number of nickels.\r\n" );
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document.write( "Then the number of dimes is 2N and the number of quarters is (21-N-2N) - (21-3N).\r\n" );
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document.write( "The \"money\" equation is\r\n" );
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document.write( "    5N + 10*(2N) + 25*(21-3N) = 275  cents.\r\n" );
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document.write( "Simplify and solve\r\n" );
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document.write( "    5N + 20N + 25*21 - 75N = 275\r\n" );
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document.write( "    -50N = 275 - 25*21\r\n" );
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document.write( "      N =  = 5.\r\n" );
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document.write( "ANSWER.  5 nickel,  2*5 = 10 dimes  and the rest 21 - 5 - 10 = 6 coins are quarters.\r\n" );
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document.write( "CHECK.   5*5 + 10*10 + 6*25 = 275 cents.    ! Correct !\r\n" );
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