document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138242>Question 1138242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Someone please help..<BR>\n" );
document.write( "Big tipper. On Monday Headley paid $1.70 for two cups of coffee and one doughnut, including the tip. On Tuesday he paid $1.65 for two doughnuts and a cup of coffee, including the tip. On Wednesday he paid $1.30 for one coffee and one doughnut, including the tip. If he always tips the same amount, then what is the amount of each item?<BR>\n" );
document.write( "I know how to do the math but I have no idea what the three equations would be... please help <BR>\n" );
document.write( "I can’t figure out and I need to show work done with three equations. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756078 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let c equal the cost for one cup of coffee.<BR>\n" );
document.write( "let d equal the cost for one doughnut.<BR>\n" );
document.write( "let t equal the cost of the tip.\r<BR>\n" );
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document.write( "your first equation is 2c + d + t = 1.70<BR>\n" );
document.write( "your second equation is c + 2d + t = 1.65<BR>\n" );
document.write( "your third equation is c + d + t = 1.30\r<BR>\n" );
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document.write( "solve the first and second equations simultaneously to get c - d = .05\r<BR>\n" );
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document.write( "solve the second and third equations simultaneously to get d = .35\r<BR>\n" );
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document.write( "since c - d = .05, then c must be equal to .4\r<BR>\n" );
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document.write( "your solution is that c = .4 and d = .35.\r<BR>\n" );
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document.write( "go back to any of the 3 equations and solve for t to get t = .55.\r<BR>\n" );
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document.write( "your solution is the price of a cup of coffee is 40 cents and the price of a doughnut is 35 cents and the tip is 55 cents.\r<BR>\n" );
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document.write( "i confirmed with all 3 original equations that this solution is correct.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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