document.write( "Question 1138137: Find the value of Tan^-1(√3). Leave your answer in terms of pi whenever appropriate.
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Algebra.Com's Answer #756072 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Not the best method, but refering to unit circle, \"tan%28alpha%29=sin%28alpha%29%2Fcos%28alpha%29=sqrt%283%29\" will work for angle \"pi%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Better Method:
\n" ); document.write( "Draw right triangle.
\n" ); document.write( "vertical leg \"sqrt%283%29\", horizontal leg 1.
\n" ); document.write( "Find hypotenuse using r,
\n" ); document.write( "\"%28sqrt%283%29%29%5E2%2B1%5E2=r%5E2\";
\n" ); document.write( "\"r=2\";\r
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\n" ); document.write( "\n" ); document.write( "Let \"alpha\" be opposite of the vertical leg of \"sqrt%283%29\".
\n" ); document.write( "\"tan%28alpha%29=%28sqrt%283%29%2F2%29%2F%281%2F2%29\" corresponding to \"alpha=pi%2F3\".
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