document.write( "Question 103922: how do you do this could you explain it to me really slow
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Algebra.Com's Answer #75606 by stanbon(75887)\"\" \"About 
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how many gallons of 50% antifreeze must be mixed with 80 gal of 20% antifreeze to get a mixture that is 40% antifreeze? Gallons of mixture/Rate/Gallons of Antifreeze\r
\n" ); document.write( "\n" ); document.write( " X .50 .50x
\n" ); document.write( " 80 .20 .20(80)
\n" ); document.write( " x+80 .40 .40(x+80)
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\n" ); document.write( "The 1st column is the amount of liguid
\n" ); document.write( "The 2nd column is the percentage of active ingredient in each amount
\n" ); document.write( "of liguid
\n" ); document.write( "The 3rd column is the actual amount of active ingredient in each amount of liquid
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active ingredient you start with + active ingredient you add = active ingredient
\n" ); document.write( "you end up with.
\n" ); document.write( "0.50x + 0.20(80) = 0.40(x+80)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50x + 20*80 = 40(x+80)
\n" ); document.write( "50x + 1600 = 40x + 3200
\n" ); document.write( "10x = 1600
\n" ); document.write( "x = 160 (this is the amount of 50% antifreeze that must be added) to the
\n" ); document.write( "20% antifreeze to end up with 40% antifreeze.
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\n" ); document.write( "Comment:
\n" ); document.write( "That is not the way I would set it up but I tried to explain the
\n" ); document.write( "setup you have to work with.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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