document.write( "Question 1138152: What is the length of the period for the following equation: y+1=3cos(pi/4)(x-2).
\n" ); document.write( "Make sure to show work.
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Algebra.Com's Answer #756057 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "\"y+=+a%2Acos%28b%28x-c%29%29%2Bd\"

\n" ); document.write( "a is the amplitude
\n" ); document.write( "b determines the period: b = 2pi/period
\n" ); document.write( "c is the phase (horizontal) shift
\n" ); document.write( "d is the vertical shift

\n" ); document.write( "The given equation, in that form, is

\n" ); document.write( "\"y+=+3%2Acos%28%28pi%2F4%29%28x-2%29%29-1\"

\n" ); document.write( "The period is determined by b; b = 2pi/period. Since b = pi/4, the period is

\n" ); document.write( "\"2pi%2F%28pi%2F4%29\" = 8
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