document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138223>Question 1138223</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Andrew travelled a distance of 39 km by jogging for 4 hours and cycling for 3 hours. He could havetravelledthesamedistancebyjoggingfor7hoursandcyclingfor2hours. Find the speed at which he was jogging and the speed at which he was cycling.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #756047 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=756047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "4j+3c = 39<BR>\n" );
document.write( "7j+2c = 39<br><BR>\n" );
document.write( "Solve the pair of linear equations by any method you choose.<br><BR>\n" );
document.write( "Here is a method you might not have seen that works very nicely for this problem.<br><BR>\n" );
document.write( "Continue the pattern shown by the two equations:<BR>\n" );
document.write( "4j+3c = 39<BR>\n" );
document.write( "7j+2c = 39  (3 more hours jogging and 1 less hour cycling gives the same total distance)<BR>\n" );
document.write( "10j+c = 39  (continue the pattern of 3 more hours jogging and 1 less hour cycling)<BR>\n" );
document.write( "13j = 39<br><BR>\n" );
document.write( "So j = 39/13 = 3; his jogging speed is 3km/hr.<br><BR>\n" );
document.write( "Then combining that with the first equation gives c = 9.<br><BR>\n" );
document.write( "ANSWER: jogging 3km/hr; cycling 9km/hr </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );