document.write( "Question 1138018: Solve cos2x = -cosx over the interval 0 ≤ x < 2pi \n" ); document.write( "
Algebra.Com's Answer #755933 by MathLover1(20849)\"\" \"About 
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\"cos%282x%29+=+-cos%28x%29\" for the interval \"0+%3C=+x+%3C+2pi\"\r
\n" ); document.write( "\n" ); document.write( " \"cos+%282x%29%2Bcos+%28x%29+=0\"..........use the following identity : \"cos++%282x+%29=+-1%2B2+cos%5E2+%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-1%2B2cos%5E2+%28x%29%29%2Bcos+%28x%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2cos%5E2+%28x%29+%2Bcos+%28x%29-1+=0\".......let \"cos+%28x%29+=u\"\r
\n" ); document.write( "\n" ); document.write( "\"2u%5E2++%2Bu-1+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2u%5E2+-u+%2B2u-1+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%282u%5E2+-u+%29%2B%282u-1%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"u%282u+-1+%29%2B%282u-1%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28u%2B1%29%282u-1%29+=0\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28u%2B1%29=0\"=>\"u=-1\"\r
\n" ); document.write( "\n" ); document.write( "if\"+%282u-1%29+=0\"=> \"u=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "since \"cos+%28x%29+=u\", we have\r
\n" ); document.write( "\n" ); document.write( "\"cos+%28x%29+=-1\" or\r
\n" ); document.write( "\n" ); document.write( "\"cos+%28x%29+=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "if \"cos+%28x+%29=-1\", and \"0%3C=x%3C2pi\", then \"x=pi+\"\r
\n" ); document.write( "\n" ); document.write( "if \"cos+%28x+%29=1%2F2\", and\"+0%3C=x%3C2pi\", than \"x=pi%2F3\", \"x=5pi%2F3+\"\r
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\n" ); document.write( "\n" ); document.write( "combine all solutions: \"x=pi%2F3\", \"x=5pi%2F3+\",\"x=pi+\"\r
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