document.write( "Question 103905: Jason traveled 120 miles at an average rate of speed. If he could have increased his speed 25 mph, he could have covered the same distance in 2/5 of an hour less time. How fast did he travel? \n" ); document.write( "
Algebra.Com's Answer #75593 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 120/X=120/(X+25)+.4 \n" ); document.write( "120/X=(120+.4X+25*.4)/(X+25) \n" ); document.write( "120/X=(120+.4X+10)/(X+25) \n" ); document.write( "120/X=(130+.4X)/(X+25) NOW CROSS MULTIPLY. \n" ); document.write( "120(X+25)=130X+.4X^2 \n" ); document.write( "120X+3000=130X+.4X^2 \n" ); document.write( ".4X^2+130X-120X-3000=0 \n" ); document.write( ".4X^2+10X-3000=0 \n" ); document.write( ".4(X^2+25X-7500)=0 \n" ); document.write( ".4(X-75)(X+100)=0 \n" ); document.write( "X-75=-0 \n" ); document.write( "X=75 ANSWER FOR THE ORIGINAL SPEED. \n" ); document.write( "75+25=100 FOR THE INCREASED SPEED. \n" ); document.write( "SPEED \n" ); document.write( "120/75=120/100+.4 \n" ); document.write( "1.6=1.2+.4 \n" ); document.write( "1.6=1.6 \n" ); document.write( " \n" ); document.write( " |