document.write( "Question 1138012: The sum of the ages of four brothers in a family is 31. If the oldest brother is 6 years less than three times the second child. The youngest is four years younger than the second child. And the third child exceeds the second by five years. How old is each of the brothers?
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Algebra.Com's Answer #755895 by josgarithmetic(39617)\"\" \"About 
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document.write( "youngest             x-4\r\n" );
document.write( "second               x\r\n" );
document.write( "third                x+5\r\n" );
document.write( "oldest              3x-6\r\n" );
document.write( "SUM                  31\r\n" );
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