document.write( "Question 1137893: 1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?\r
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document.write( "2. Angie bought some golf balls for $5. If each ball had cost $0.25 less, she could have purchased one more ball for the same amount of money. How many balls did Angie buy?
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Algebra.Com's Answer #755876 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! 1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest? \n" ); document.write( " \n" ); document.write( "6% interest rate: \n" ); document.write( "Principal = 300 \n" ); document.write( "Rate = 0.06 \n" ); document.write( "Interest = 300 * 0.06 = 18 \n" ); document.write( " \n" ); document.write( "Other interest rate: \n" ); document.write( "Principal = 400 \n" ); document.write( "Rate = 52/400 = 0.13 \n" ); document.write( "Interest = 70 - 18 = 52 \n" ); document.write( " \n" ); document.write( "To yield MORE than $70 worth of interest, the $400 must be invested at a rate HIGHER than 13%. \n" ); document.write( " \n" ); document.write( "2. Angie bought some golf balls for $5. If each ball had cost $0.25 less, she could have purchased one more ball for the same amount of money. How many balls did Angie buy? \n" ); document.write( " \n" ); document.write( "c = cost of each ball \n" ); document.write( "n = number of balls \n" ); document.write( " \n" ); document.write( "c * n = 5 \n" ); document.write( "(c - 0.25) * (n + 1) = 5 \n" ); document.write( " \n" ); document.write( "This means: \n" ); document.write( "c * n = (c - 0.25) * (n + 1) \n" ); document.write( " \n" ); document.write( "Simplify: \n" ); document.write( "cn = cn - 0.25n + c - 0.25 \n" ); document.write( " \n" ); document.write( "Solve for c: \n" ); document.write( "0 = c - 0.25n - 0.25 \n" ); document.write( " \n" ); document.write( "c = 0.25n + 0.25 \n" ); document.write( " \n" ); document.write( "From earlier, we know: \n" ); document.write( "c * n = 5 \n" ); document.write( " \n" ); document.write( "Substitute 0.25n + 0.25 for c: \n" ); document.write( "c * n = 5 \n" ); document.write( " \n" ); document.write( "(0.25n + 0.25) * n = 5 \n" ); document.write( " \n" ); document.write( "Solve for n: \n" ); document.write( "0.25n² + 0.25n = 5 \n" ); document.write( " \n" ); document.write( "0.25n² + 0.25n - 5 = 0 \n" ); document.write( " \n" ); document.write( "Use quadratic formula. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "You will find that n = 4 and n = -5. Since the number of balls purchased cannot be a negative number, you can throw out n = -5. We are left with n = 4. \n" ); document.write( " \n" ); document.write( "We now know Angie bought 4 balls. \n" ); document.write( " \n" ); document.write( "From earlier: \n" ); document.write( "c * n = 5 \n" ); document.write( " \n" ); document.write( "Substitute '4' for n: \n" ); document.write( "c * 4 = 5 \n" ); document.write( " \n" ); document.write( "Solving for c, we find that c = 1.25. \n" ); document.write( " \n" ); document.write( "In summary, Angie bought four balls at $1.25 apiece. (Had each ball been $0.25 cheaper, she could've bought five balls at $1.00 apiece.) |