document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103909>Question 103909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50.<BR>\n" );
document.write( "set up an equation for the perimeter involving only L, the length of the rectangle.<BR>\n" );
document.write( "sove this equation algebraically to find the length of the rectange. find the width as well.\r<BR>\n" );
document.write( "\n" );
document.write( "thanks for the help-renee </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75586 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-5 <BR>\n" );
document.write( "PERIMETER=2L+2W<BR>\n" );
document.write( "50=2L+2(L-5)<BR>\n" );
document.write( "50=2L+2L-10<BR>\n" );
document.write( "50=4L-10<BR>\n" );
document.write( "4L=50+10<BR>\n" );
document.write( "4L=60<BR>\n" );
document.write( "L=60/4<BR>\n" );
document.write( "L=15 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "W=15-5<BR>\n" );
document.write( "W=10 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*15+2*10=50<BR>\n" );
document.write( "30+20=50<BR>\n" );
document.write( "50=50<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );