document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1137979>Question 1137979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a certain firm invests $3000 at 5.75% annual interest compounded monthly. find the value of the investment in 6 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #755849 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=755849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is 3000(1+(.0575/12))^72, the 72 being the number of months in 6 years.<BR>\n" );
document.write( "=$4232.48, round at the end.<BR>\n" );
document.write( "Calculate 1+ (.0575/12), then raise it to the 72 nd power, then multiply by $3000. </SPAN>\n" );
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