document.write( "Question 1137964: 9 years ago a woman was 3 times as old as her son, in 8 years from now the sum of their ages = 78 \n" ); document.write( "
Algebra.Com's Answer #755834 by Boreal(15235)\"\" \"About 
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today woman is x, son is y
\n" ); document.write( "x-9=3(y-9)
\n" ); document.write( "x-9=3y-27
\n" ); document.write( "3y-x=18
\n" ); document.write( "in 8 years x+8 and y+8 and that sum is 78, so x+y+16=78
\n" ); document.write( "x+y=62
\n" ); document.write( "x=62-y
\n" ); document.write( "so 3y-62+y=18
\n" ); document.write( "4y=80
\n" ); document.write( "y=20 son
\n" ); document.write( "x=42 mother
\n" ); document.write( "nine years earlier it was 33 and 11
\n" ); document.write( "8 years from now it will be 50 and 28
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