document.write( "Question 1137943: Please help me solve this system of equations:
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document.write( "y=2x+1
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document.write( "y=4/7x +1
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Algebra.Com's Answer #755809 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equations are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 2x + 1 \n" ); document.write( "y = (4/7)x + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = 2x - (4/7) * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 7 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = 14x - 4x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get 0 = 10x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 0:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 2x + 1 becomes y = 1 \n" ); document.write( "y = (4/7)x + 1 becomes y = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the common solution to both equations is when x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 0 in both equations, y = 0 in both equations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |