document.write( "Question 1137820: Suppose that a single fair die is rolled one time. Let events A and B be defined as:\r
\n" ); document.write( "\n" ); document.write( "A = { 1, 4, 5 } and B = { 2, 4, 5, 6 }\r
\n" ); document.write( "\n" ); document.write( "Are A and B independent events? Show why or why not? I cant figure this problem out
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Algebra.Com's Answer #755706 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "I'm assuming the set notation refers to the outcome of rolling the die
\n" ); document.write( "A = {1,4,5} = rolling a 1, 4 or 5
\n" ); document.write( "B = {2,4,5,6} = rolling a 2, 4, 5, or 6\r
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\n" ); document.write( "\n" ); document.write( "There are 3 ways to roll an outcome in event A, out of 6 total, so
\n" ); document.write( "P(A) = 3/6 = 1/2\r
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\n" ); document.write( "\n" ); document.write( "There are 4 items in set B, so
\n" ); document.write( "P(B) = 4/6 = 2/3\r
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\n" ); document.write( "\n" ); document.write( "If A and B were independent, then this equation would be true
\n" ); document.write( "P(A and B) = P(A)*P(B)
\n" ); document.write( "P(A and B) = (1/2)*(2/3)
\n" ); document.write( "P(A and B) = 1/3
\n" ); document.write( "We'll keep this value in mind\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "C = the event in which both A and B happen at the same time
\n" ); document.write( "In other words, event C is rolling either a 4 or 5 since these values are found in both set A = {1,4,5} and set B = {2,4,5,6}. We can say that set C is the intersection of A and B
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\n" ); document.write( "\n" ); document.write( "C = {4,5}
\n" ); document.write( "We have 2 ways to get a value in set C, out of 6 ways to roll a die
\n" ); document.write( "P(C) = 2/6
\n" ); document.write( "P(C) = 1/3
\n" ); document.write( "we get 1/3 just like with the previous computation\r
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\n" ); document.write( "\n" ); document.write( "We see that P(A and B) = P(C) = P(A)*P(B) is true, so therefore we have shown A and B are independent events.
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