document.write( "Question 1137789: Find the sum of the arithmetic series with first term 1,common difference 3,and last term hundred \n" ); document.write( "
Algebra.Com's Answer #755678 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! The sum of the first n terms of an arithmetic sequence is \n" ); document.write( ": \n" ); document.write( "Sum = (n/2) * (2a +d(n-1)), where a is the first term, n is the number of terms to sum, and d is the common difference \n" ); document.write( ": \n" ); document.write( "We are given a=1, d=3 \n" ); document.write( ": \n" ); document.write( "We need to determine the nth term of this sequence which is 100 \n" ); document.write( ": \n" ); document.write( "The formula for the nth term of an arithmetic sequence is \n" ); document.write( ": \n" ); document.write( "x(n) = x(1) +d(n-1), where x(1) is the first term \n" ); document.write( ": \n" ); document.write( "we are given that the nth term is 100 \n" ); document.write( ": \n" ); document.write( "100 = 1 +3(n-1) \n" ); document.write( ": \n" ); document.write( "100 = 1 +3n-3 \n" ); document.write( ": \n" ); document.write( "3n = 102 \n" ); document.write( ": \n" ); document.write( "n = 34 \n" ); document.write( ": \n" ); document.write( "sum = (34/2) * (2(1) +3(34-1)) \n" ); document.write( ": \n" ); document.write( "******************************** \n" ); document.write( "sum = 17 * (2 +99) = 1717 \n" ); document.write( "******************************** \n" ); document.write( ": \n" ); document.write( " |