document.write( "Question 1137718: The number of chocolate chips in an​ 18-ounce bag of chocolate chip cookies is approximately normally distributed with mean 1252 and standard deviation 129 chips.
\n" ); document.write( "​(a) What is the probability that a randomly selected bag contains between 1000 and 1500 chocolate​ chips?
\n" ); document.write( "​(b) What is the probability that a randomly selected bag contains fewer than 1050 chocolate​ chips?
\n" ); document.write( "​(c) What proportion of bags contains more than 1225 chocolate​ chips?
\n" ); document.write( "​(d) What is the percentile rank of a bag that contains 1425 chocolate​ chips?
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Algebra.Com's Answer #755582 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "(1000-1252)/129=-1.95
\n" ); document.write( "(1500-1252)/129=+1.92
\n" ); document.write( "That z value range has probability of 0.9470\r
\n" ); document.write( "\n" ); document.write( "fewer than 1050 is a z<(-202/129)=-1.57
\n" ); document.write( "This probability is 0.0582\r
\n" ); document.write( "\n" ); document.write( ">1225 is a z>(27/129) or 0.4168\r
\n" ); document.write( "\n" ); document.write( "1425 is a z value of (173/129) or 1.34
\n" ); document.write( "The probability of less than that is 0.9099 or 91st percentile.
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