document.write( "Question 1137696: Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 97 th percentile. \n" ); document.write( "
Algebra.Com's Answer #755569 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 97%th percentile is z of +1.88 \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "1.88=(x-50)/7 \n" ); document.write( "x=63.16 or 63.2 is 97th percentile. \n" ); document.write( " |